MATH SOLVE

5 months ago

Q:
# ABCD is a parallelogram and this figure is NOT drawn to scale.

Accepted Solution

A:

The angle does not matter. Think of it as finding the other side to a triangle. Use [tex]a ^{2} +b^2 =c^2 [/tex]

a=39 (line AB)

b=b (the leg we need to find)

c=89 (line BD)

[tex]39^2 + b^2 = 89^2 [/tex]

[tex]1521 + b^2 = 7921 [/tex]

(subtract the 1521 from both sides)

[tex]b^2 = 6400[/tex]

(square root both sides)

[tex] \sqrt{(b^2)} = \sqrt{6400} [/tex]

b = 80

AD=80

a=39 (line AB)

b=b (the leg we need to find)

c=89 (line BD)

[tex]39^2 + b^2 = 89^2 [/tex]

[tex]1521 + b^2 = 7921 [/tex]

(subtract the 1521 from both sides)

[tex]b^2 = 6400[/tex]

(square root both sides)

[tex] \sqrt{(b^2)} = \sqrt{6400} [/tex]

b = 80

AD=80