In a randomly generated sequence of 24 binary digits (0s and 1s), what is the probability that exactly half of the digits are 0? a. 1352078 b. 1.295 c. 0 d. 0.1612 Please select the best answer from the choices provided A B C D

P(X=12) = 24C12 * (0.5)^12 * (0.5)^12
= 0.161 to 3 d.p.

not entirely sure, but i think it's that