Q:

What are the solutions of 3x2 + 15 = βˆ’6x

Accepted Solution

A:
Answer:x = -1 + 2 i or x = -1 - 2 iStep-by-step explanation:Solve for x: 3 (x^2 + 5) = -6 x Expand out terms of the left hand side: 3 x^2 + 15 = -6 x Add 6 x to both sides: 3 x^2 + 6 x + 15 = 0 Divide both sides by 3: x^2 + 2 x + 5 = 0 Subtract 5 from both sides: x^2 + 2 x = -5 Add 1 to both sides: x^2 + 2 x + 1 = -4 Write the left hand side as a square: (x + 1)^2 = -4 Take the square root of both sides: x + 1 = 2 i or x + 1 = -2 i Subtract 1 from both sides: x = -1 + 2 i or x + 1 = -2 i Subtract 1 from both sides: Answer: x = -1 + 2 i or x = -1 - 2 i