Convert -squareroot of 3 +i into CIS form using exact radian measures
Accepted Solution
A:
we need to find its magnitude (r) and argument (θ).
First, let's find the magnitude (r):
|r| = $$ \sqrt{(\left(-\sqrt{3}\right)^2+i^2)}=\sqrt{3+1}=2 $$
Next, let's find the argument (θ):
$$θ = atan2(Im, Re) = atan2(1, -√3) = π/6$$
Therefore, in CIS form, the complex number -√3 + i can be represented as:
2 * cis(π/6)