Convert -squareroot of 3 +i into CIS form using exact radian measures

Accepted Solution

we need to find its magnitude (r) and argument (θ). First, let's find the magnitude (r): |r| = $$ \sqrt{(\left(-\sqrt{3}\right)^2+i^2)}=\sqrt{3+1}=2 $$ Next, let's find the argument (θ): $$θ = atan2(Im, Re) = atan2(1, -√3) = π/6$$ Therefore, in CIS form, the complex number -√3 + i can be represented as: 2 * cis(π/6)