MATH SOLVE

6 months ago

Q:
# Craig measured these three rectangles.

Accepted Solution

A:

Answer:Step-by-step explanation:Perimeter of a rectangle is expressed as (2 length + 2 width) = 2(L + W)A) The length of rectangle A is y + 1The width of rectangle A is xPerimeter of rectangle A = 2(y + 1 + x) = 2y + 2 + 2x = 2x + 2y + 2The length of rectangle B is 2x - 2yThe width of rectangle B is x + 1Perimeter of rectangle B = 2(2x - 2y+ x + 1) = 4x - 4y + 2x + 2) = 4x + 2x - 4y + 2= 6x - 4y + 2The length of rectangle C is 3x + 3yThe width of rectangle C is 2x - 3Perimeter of rectangle C = 2(3x + 3y + 2x - 3) = 6x + 6y + 4x - 6) = (6x + 6y + 4x - 6)= 10x + 6y - 6B) The combined perimeters will be the sum if perimeter of rectangle A, perimeter of rectangle B and perimeter of rectangle C. It becomes 2x + 2y + 2 + 6x - 4y + 2 + 10x + 6y - 6 Collecting like terms2x + 6x + 10x + 2y + 6y - 4y + 2 + 2 - 6The combined perimeter = 18x + 4y - 2