Q:

d) Use the method of elimination and substitute the values found in the system of equations: 2𝑥+2𝑦=13 8𝑥+3𝑦=27

Accepted Solution

A:
$$2x+2y=13,8x+3y=27$$
$$8\times 2x+8\times 2y=8\times 13,2\times 8x+2\times 3y=2\times 27$$
$$16x+16y=104,16x+6y=54$$
$$16x-16x+16y-6y=104-54$$
$$16y-6y=104-54$$
$$10y=104-54$$
$$10y=50$$
$$y=5$$
$$8x+3\times 5=27$$
$$8x+15=27$$
$$8x=12$$
$$x=\frac{3}{2}$$
$$x=\frac{3}{2},y=5$$