Q:

# hi,i need help with figuring out how to solve real world word problems with polynomial and integer expressions.Thankyou

Accepted Solution

A:
Part a.

Fixed charge for the month: $30 Charge per hour:$0.50 daytime
Charge per hour: $0.25 nights and weekends Let's say in one month, a person parks for d hours of daytime and n hours of nights and weekends. The total monthly charge would be cost = 30 + 0.50d + 0.25n Now let's see what Trent did. He parked for 47 hours in one month. h of the 47 hours are nights and weekends. Let x = number of daytime hours. x + h = 47 x = 47 - h He parked h hours of night and weekends, and he parked 47 - h hours of daytime. Now we use h for night and weekend hours and 47 - h for daytime hours in the expression above. cost = 30 + 0.50d + 0.25n cost = 30 + 0.50(47 - h) + 0.25h Answer to part a.: 30 + 0.50(47 - h) + 0.25h Part b. We are told the actual number of night and weekend hours, which we called h above, is 12. h = 12. Now we use the cost expression we found in part a. with 12 in for h. cost = 30 + 0.50(47 - h) + 0.25h cost = 30 + 0.50(47 - 12) + 0.25(12) cost = 30 + 0.50(35) + 0.25(12) cost = 30 + 17.50 + 3 cost = 50.5 Answer to part b.:$50.50