MATH SOLVE

5 months ago

Q:
# Indicate a general rule for the nth term of this sequence. 6a, 3a, 0, -3a, -6a, . . .

Accepted Solution

A:

6a-(n-1)(3a) is the nth term

Expanding we get 6a-3an+3a=9a-3an=3a(3-n)

SOLUTION: nth term is 3a(3-n)

Expanding we get 6a-3an+3a=9a-3an=3a(3-n)

SOLUTION: nth term is 3a(3-n)