MATH SOLVE

8 months ago

Q:
# The cost equation for a company to install x square feet of brick pathway is C = 234 +14x, and the cost equation for a second company to install x square feet ofbrick pathway is C = 23x. What is the area of the path that could be built by either company for the same cost? How much would it cost?What is the area of the path that could be built by either company for the same cost? Select the correct choice below and fill in the answer box within your choice.square feet.O A The area of the path that could be built by either company for the same cost is(Type a whole number.)OB. The costs are never equalHow much would it cost? Select the correct choice below and fill in the answer box within your choiceO A It would cost $(Type a whole number.)OB. The costs are never equal

Accepted Solution

A:

Answer:Step-by-step explanation:Let A be first company Install x square feet of brick pathway costC₁ = 234 + 14xAnd company B to install x feet of brick charge C₂ = 23xIf we make C₁ = C₂ we will find the area in which the cost will be the same for the two companiesThereforeC₁ = C₂234 + 14x = 23x - 23x + 14x = -234 -9x = - 234 x = 234/9 x = 26 ft² is the area that could be installed by either company at the same costHow much would it costC₁ = 234 + 14x C₂ = 23*xC₁ = 234 + 364 C₂ = 23*26C₁ = 598 monetary units C₂ = 598 monetary units