What are the dimensions of the lightest​ open-top right circular cylindrical can that will hold a volume of 2744 cmcubed3​?

Answer: r=2.808cm    h = 100cm then we get volume of cylinder that is 2744 As explained belowStep-by-step explanation:Volume of cylinder = πr²hSurface area of cylinder = 2πrh +πr²                                (1) h= 2744 /πr²put value oh h in equation (1)Area =[2πr] 2744 /πr²         =[5488/r +πr²]dA/dx=0                                       i.e     2πr=5488/r²Solving this r.r= ∛5488/2π                        =2.808taking second derivation we get 100