MATH SOLVE

8 months ago

Q:
# What is the distance between points (8,3) and (8,-6) on a coordinate plane?

Accepted Solution

A:

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:

[tex]\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]

"d" represents the distance and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

[tex]\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(8-8)^2+(-6-3)^2}}\\\\ \mathsf{d=\sqrt{(0)^2+(-9)^2}}\\\\ \mathsf{d=\sqrt{0+81}}\\\\ \mathsf{d=\sqrt{81}}\\\\ \underline{\mathsf{d=9}}[/tex]

The answer is 9 u.c.

[tex]\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]

"d" represents the distance and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

[tex]\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(8-8)^2+(-6-3)^2}}\\\\ \mathsf{d=\sqrt{(0)^2+(-9)^2}}\\\\ \mathsf{d=\sqrt{0+81}}\\\\ \mathsf{d=\sqrt{81}}\\\\ \underline{\mathsf{d=9}}[/tex]

The answer is 9 u.c.