Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

Answer:The dinner costed $48 in total.Step-by-step explanation:The amount of bill paid by Will = 1/4 of billAmount of bill paid by Micah and Sue  1: 3Let us assume the common factor in the ratio  = mSo, the amount paid by Micah = 1 x (m) = mThe amount paid by Sue  = 3 x (m)  = 3 mAlso, amount paid by Sue  = $15 + Amount paid by WillSo, the amount paid by Will =  amount paid by Sue - $15   = 3 m - $15Total Bill  = Bill amount paid by ( Will + Micah + Sue)                  =   m + 3 m + 3 m - 15  = 7 m - 15Now, As will paid 1/4 of total bill.⇒[tex]\frac{1}{4} \times (7 m -15)  = 3m -15\\ \implies (7m - 15)  = 12  m - 60\\\implies 45 = 5 m \\\implies  m = 45/5 = 9[/tex]or,  m = 9Now, the total bill = 7 m - 15  = 7(9) - 15  =  $48Hence, the dinner costed $48 in total.