explain the answer because im stuck

Answer:The Proof is given below.Step-by-step explanation:Given:[tex]\overline{HF}[/tex]  bisect ∠ EHG.i.e∴ ∠EHF ≅ ∠ GHF[tex]\overline{EH} \cong \overline{GH}[/tex]  To Prove:[tex]\overline{EF} \cong \overline{GF}[/tex]  Proof:In  Δ EHF and Δ GHF     EH ≅ GH     ………............{Given} ∠ EHF ≅ ∠ GHF     …………..{EF bisect ∠ EHG as given above}      HF ≅ HF     ………............{Reflexive Property} Δ EHF ≅ Δ GHF …................{ By Side-Angle-Side test} ∴ EF ≅ GF........{corresponding parts of congruent triangles (c.p.c.t).}[tex]\overline{EF} \cong \overline{GF}[/tex]  ....... PROVED