MATH SOLVE

10 months ago

Q:
# Find x if the angles of a quadrilateral are 2x, 3x, 4x, and 5x

Accepted Solution

A:

To solve this we are going to take advantage of the fact the the sum of the interior angles of a quadrilateral is always 360°. So, we can add up all our angles and set them equal to 360°:

[tex]2x+3x+4x+5x=360[/tex]

Now, we just need to solve for [tex]x[/tex]:

[tex]2x+3x+4x+5x=360[/tex]

[tex]14x=360[/tex]

[tex]x= \frac{360}{14} [/tex]

[tex]x= \frac{180}{7} [/tex]

We can conclude that the value of [tex]x[/tex] in our quadrilateral is [tex] \frac{180}{7} [/tex]°, or we can conclude that [tex]x[/tex] is approximately 25.7° (in decimal form).

[tex]2x+3x+4x+5x=360[/tex]

Now, we just need to solve for [tex]x[/tex]:

[tex]2x+3x+4x+5x=360[/tex]

[tex]14x=360[/tex]

[tex]x= \frac{360}{14} [/tex]

[tex]x= \frac{180}{7} [/tex]

We can conclude that the value of [tex]x[/tex] in our quadrilateral is [tex] \frac{180}{7} [/tex]°, or we can conclude that [tex]x[/tex] is approximately 25.7° (in decimal form).