MATH SOLVE

9 months ago

Q:
# Joel wants to fence off a triangular portion of his yard yard for his chickens. The three pieces of fencing he has to use are 8 feet, 15 feet and 20 feet

Accepted Solution

A:

the complete question in the attached figure

we know that

in a right triangle

c²=a²+b²

c=20 ft

a=8ft

b=15 ft

so

c²------> 20²----> 400

and

a²+b²-----> 8²+15²------> 64+225-----> 289

so

400 is not 289

therefore

Part A)

the answer is

Joel is not be able to make a right triangle with his fence

Part B)

if Joel cut the longest piece of fencing in order to make a right triangle

then

a²+b²=289

so

c²=√289-------> c=17 ft

the perimeter of the fence is

17+8+15-----> perimeter=40 ft

if Joel takes 30 sec to install----------> 1 ft of fencing

X--------------------------------------> 40 ft

x=40*30-----> x=1200 sec------> x=1200/60----> x=20 minutes

Part B)

the answer is

20 minutes

we know that

in a right triangle

c²=a²+b²

c=20 ft

a=8ft

b=15 ft

so

c²------> 20²----> 400

and

a²+b²-----> 8²+15²------> 64+225-----> 289

so

400 is not 289

therefore

Part A)

the answer is

Joel is not be able to make a right triangle with his fence

Part B)

if Joel cut the longest piece of fencing in order to make a right triangle

then

a²+b²=289

so

c²=√289-------> c=17 ft

the perimeter of the fence is

17+8+15-----> perimeter=40 ft

if Joel takes 30 sec to install----------> 1 ft of fencing

X--------------------------------------> 40 ft

x=40*30-----> x=1200 sec------> x=1200/60----> x=20 minutes

Part B)

the answer is

20 minutes