MATH SOLVE

7 months ago

Q:
# Of the money in a bank account, Cachistolo Atistoy withdraws first the 3/8; then the 7/10 of what was left. If the current balance is $1893000, how much did he have at the beginning?

Accepted Solution

A:

To find out how much Cachistolo Atistoy had in the bank account at the beginning, we can work backward using the information provided.
Let's denote the initial amount of money in the account as "x."
First, Cachistolo Atistoy withdraws 3/8 of the initial amount.
So, the amount remaining after this withdrawal is (1 - 3/8) * x = (5/8) * x.
Next, he withdraws 7/10 of what was left after the first withdrawal.
So, the final balance is (1 - 7/10) * (5/8) * x = (3/16) * x.
Given that the current balance is $1,893,000, we can set up the equation:
(3/16) * x = $1,893,000
Now, solve for x:
x = ($1,893,000 * 16) / 3
x = $10,096,000
So, Cachistolo Atistoy had $10,096,000 in the bank account at the beginning.