MATH SOLVE

8 months ago

Q:
# solve the system of linear equations. separate the x- and y- values with a coma. -x=62-18y2x=38-18y

Accepted Solution

A:

Solve the following system:

{-x = 62 - 18 y | (equation 1){2 x = 38 - 18 y | (equation 2)

Express the system in standard form:

{-x + 18 y = 62 | (equation 1){2 x + 18 y = 38 | (equation 2)

Swap equation 1 with equation 2:

{2 x + 18 y = 38 | (equation 1){-x + 18 y = 62 | (equation 2)

Add 1/2 Γ (equation 1) to equation 2:

{2 x + 18 y = 38 | (equation 1){0 x+27 y = 81 | (equation 2)

Divide equation 1 by 2:

{x + 9 y = 19 | (equation 1){0 x+27 y = 81 | (equation 2)

Divide equation 2 by 27:

{x + 9 y = 19 | (equation 1){0 x+y = 3 | (equation 2)

Subtract 9 Γ (equation 2) from equation 1:

{x+0 y = -8 | (equation 1){0 x+y = 3 | (equation 2)

Collect results:

Answer: {x = -8 , y = 3

{-x = 62 - 18 y | (equation 1){2 x = 38 - 18 y | (equation 2)

Express the system in standard form:

{-x + 18 y = 62 | (equation 1){2 x + 18 y = 38 | (equation 2)

Swap equation 1 with equation 2:

{2 x + 18 y = 38 | (equation 1){-x + 18 y = 62 | (equation 2)

Add 1/2 Γ (equation 1) to equation 2:

{2 x + 18 y = 38 | (equation 1){0 x+27 y = 81 | (equation 2)

Divide equation 1 by 2:

{x + 9 y = 19 | (equation 1){0 x+27 y = 81 | (equation 2)

Divide equation 2 by 27:

{x + 9 y = 19 | (equation 1){0 x+y = 3 | (equation 2)

Subtract 9 Γ (equation 2) from equation 1:

{x+0 y = -8 | (equation 1){0 x+y = 3 | (equation 2)

Collect results:

Answer: {x = -8 , y = 3