The cross section of a parabolic reflector has a vertical axis of symmetry with its vertex at (0,0) . The focus of the reflector is 6 feet above the vertex. The reflector extends 4.5 feet to either side of the vertex. What is the depth of the reflector? Round your answer to the nearest hundredth.

Answer:The depth of the reflector is 0.84 feetStep-by-step explanation:(See the figure below)The equation of a parabola centered at the origin with an axis of symmetry on y-axis is:[tex] x^{2}=4py [/tex] (1)With p the distance from the origin to the focus using p=6, the equation (1) of the parabola becomes:[tex] x^{2}=4(6)y=24y [/tex] (2)Note that the point B is on the parabola, so this point should satisfy the parabola equation (2) that allow us to use the value x=4.5 to find the y value associated to it, that it is the depth (h) of the reflector:[tex](4.5)^{2}=24y [/tex], solving for y[tex]y=\frac{(4.5)^{2}}{24}\approx0.84\,ft [/tex]