The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. the equation of the circle then changes to (x – 30)2 + (y – 16)2 = (r2)2, and the circle still passes through the origin. what are the values of r1 and r2?a.r1 = 10 and r2 = 17b.r1 = 10 and r2 = 34c.r1 = 20 and r2 = 17d.r1 = 20 and r2 = 34
Accepted Solution
A:
d. let x=0 and y=0, we get [tex] 12^2+16^2 =r _1^2 [/tex] and [tex] 30^2+16^2 = r_2^2 [/tex] so r1=20 and r2=34