MATH SOLVE

4 months ago

Q:
# The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. the equation of the circle then changes to (x β 30)2 + (y β 16)2 = (r2)2, and the circle still passes through the origin. what are the values of r1 and r2?a.r1 = 10 and r2 = 17b.r1 = 10 and r2 = 34c.r1 = 20 and r2 = 17d.r1 = 20 and r2 = 34

Accepted Solution

A:

d.

let x=0 and y=0,

we get [tex] 12^2+16^2 =r _1^2 [/tex]

and [tex] 30^2+16^2 = r_2^2 [/tex]

so r1=20 and r2=34

let x=0 and y=0,

we get [tex] 12^2+16^2 =r _1^2 [/tex]

and [tex] 30^2+16^2 = r_2^2 [/tex]

so r1=20 and r2=34