Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general admissions sold as there were kids tickets, and the total receipts were $7750, how many of each type of ticket were sold?
Accepted Solution
A:
There was 3000 general admission tickets sold and 500 kid ticket sold.
How did I get this?
First, we need to see what information we have. $2.50 = General admission tickets = (G) $0.50 = kids tickets = (K) There were 6x as many general admission tickets sold as kids. G = 6K
We need two equations: G = 6K $2.50G + $.50K = $7750 Since, G = 6K we can substitute that into the 2nd equation.
2.50(6K) + .50K = 7750 Distribute 2.50 into the parenthesis
15K + .50K = 7750 combine like terms
15.50K = 7750 Divide both sides by 15.50, the left side will cancel out.
K = 7750/15.50 K = 500 tickets So, 500 kid tickets were sold.
Plug K into our first equation (G = 6k)
G = 6*500 G = 3000 tickets
So, 3000 general admission tickets were sold,
Let's check this:
$2.50(3000 tickets) = $7500 (cost of general admission tickets) $.50(500 tickets) = $250 (cost of general admission tickets) $7500 + $250 = $7750 (total cost of tickets)