Q:

Two similar parallelograms have areas 125 m 2 and 80 m 2 . the height of the larger parallelogram is 10 m. what are the lengths of the bases of both parallelograms? solved

Accepted Solution

A:
To solve this problem you must follow the proccedure shown below:

 You have that:

 - Two similar parallelograms have areas 125 m².
 - The height of the larger parallelogram is 10 m. Then, you have: 

 125=10x

 x: the base of the larger parallelogram

 x=125/10
 x=12.5 m

 The ratio is:

 b/h=12.5/10
 b=1.25h

 - The area of the smaller parallelogram is 80 m², then, you have:

 80=bh

 When you susbstitute b=1.25h into 80=bh, you obtain the value of "h":

 80=(1.25h)h
 80=1.25h²
 h=√(80/1.25)
 h=8 

 Then, the other base is:

 b=1.25(8)
 b=10 m

 The answer is: The base of the smaller parallelogram is 10 m and the base of the larger parallelogram is 8 m.