Urgent Math help PLEASE. Few Questions!! PLEASE!!!1. Find three consecutive even integers, such that 8 times of the first integer 6 more than the sum of second and third integers. 2. Find the measure of an angle whose supplement id three times its complement.Hint: Supplement and complement of an angle are (180 - 0)* and (90 - 0)*

1. The integers are: 2,4 and 62. The angle is 45°Step-by-step explanation:1. Find three consecutive even integers, such that 8 times of the first integer 6 more than the sum of second and third integers.Let x be the first even integer then net two integers will be x+2 and x+4According to the given statement[tex]8x=x+2+x+4+6\\8x=2x+12[/tex]Subtracting 2x from both sides[tex]8x-2x=2x+12-2x\\6x=12[/tex]Dividing both sides by 6[tex]\frac{6x}{6}=\frac{12}{6}\\x=2[/tex]The other integers will be:x+2 = 2+2 = 4x+4 = 2+4 = 6Hence,The integers are: 2,4 and 62. Find the measure of an angle whose supplement id three times its complement.Let x be the required angle then its supplement will be 180-xand complement will be 90-xThen according to given statement[tex]180-x=3(90-x)\\180-x=270-3x[/tex]Adding 3x on both sides[tex]180-x+3x=270-3x+3x\\180+2x=270[/tex]Subtracting 180 from both sides[tex]180+2x-180=270-180\\2x=90[/tex]Dividing both sides by 2[tex]\frac{2x}{2}=\frac{90}{2}\\x=45[/tex]Hence,The angle is 45°Keywords: Angles, IntegersLearn more about linear equations at:brainly.com/question/12884373brainly.com/question/12896802#LearnwithBrainly