Use the zero product property to find the solutions to the equation 6x^2-5x=56

Answer:x ∈ {-8/3, 7/2}Step-by-step explanation:6x² -5x -56 = 0 . . . . . subtract the constant(3x +8)(2x -7) = 0 . . . .factor*The zero product property says the product will be zero only when one (or both) of the factors is zero.First Factor... 3x +8 = 0... x + 8/3 = 0 . . . . divide by the coefficient of x... x = -8/3 . . . . . . subtract 8/3Second Factor... 2x -7 = 0 . . . . . . set the factor to zero... x -7/2 = 0 . . . . . divide by the coefficient of x... x = 7/2 . . . . . . . add 7/2_____*Comment on factoringThere are various ways to do this. In basic terms, we want to find numbers that are factors of the product 6·(-56) whose sum is -5. We found those numbers to be -21 and 16. Then we can rewrite the -5x term using these numbers and factor by grouping.... 6x² -5x -56 = (6x² -21x) +(16x -56) = 3x(2x -7) +8(2x -7) = (3x +8)(2x -7)