What is the remainder when 4x4 − 10x3 + 14x2 + 7x − 19 is divided by 2x − 1
Accepted Solution
A:
Using long division, we have
___________________ 2x-1 | 4x^4-10x³+14x²+7x-19
Next, we divide the first term of 2x-1 by the first term of 4x^4-10x³+14x²+7x-19 to get 4x^4/2x=2x³ (since 4/2=2 and to divide exponents you subtract the denominator from the numerator). Next, we put our 2x³ on the top and multiply (2x-1) by that. With the result of (2x-1) and 2x³, we multiply that by -1 and add it to 4x^4-10x³+14x²+7x-19, looking like