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MATH SOLVE
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X^4 dy/dx + x^3y = -sec(xy)
7 months ago
Q:
x^4 dy/dx + x^3y = -sec(xy)
Accepted Solution
A:
Solve using substitution
$:{\quad}y=\frac{\arcsin(\frac{1}{2x^{2}}+c_{1})}{x}+\frac{2Οn}{x},y=\frac{Ο}{x}+\frac{\arcsin(-\frac{1}{2x^{2}}-c_{1})}{x}+\frac{2Οn}{x}$
$y=\frac{\arcsin(\frac{1}{2x^{2}}+c_{1})}{x}+\frac{2Οn}{x},y=\frac{Ο}{x}+\frac{\arcsin(-\frac{1}{2x^{2}}-c_{1})}{x}+\frac{2Οn}{x}$