MATH SOLVE

5 months ago

Q:
# Christian sold tickets to the game. Good seats were $5 each and poor seats cost $2 each. 210 people attended and paid $660. Write a system of linear equations that can be used to find how many good seats (g) and How many poor seats (p) were sold.

Accepted Solution

A:

Let g represent the # of good seats and p the # of poor ones.

Then g + p = 210 seats. Then p = 210 - g.

Revenue: ($5)g + ($2)p = $660. Substituting 210 - g for p,

($5)g + ($2)(210 - g) = $660

Simplifying, 5g + 420 - 2g = 660 => 3g = 240 => g = 80

Then there were 80 good seats and (210-80), or 130, poor seats.

Then g + p = 210 seats. Then p = 210 - g.

Revenue: ($5)g + ($2)p = $660. Substituting 210 - g for p,

($5)g + ($2)(210 - g) = $660

Simplifying, 5g + 420 - 2g = 660 => 3g = 240 => g = 80

Then there were 80 good seats and (210-80), or 130, poor seats.