MATH SOLVE

6 months ago

Q:
# The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is at 2, negative 3. Point B is at negative 3, negative 4. Point C is at negative 4, 2. Point D is at 2, 4. Point E is at 3, 1. Point F is at negative 2, 3. Part A: Using the graph above, create a system of inequalities that only contains points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points) Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points) Part C: William can only attend a school in his designated zone. William's zone is defined by y < βx β 1. Explain how you can identify the schools that William is allowed to attend. (2 points)

Accepted Solution

A:

Part A;

There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is

y β€ x

y β₯ -2x

The system of equation above represent all the points in the first quadrant of the coordinate system.

The area above the line y = -2x and to the right of the line y = x is shaded.

Part B:

It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:

-3 β€ 2

-3 β₯ -2(2) β -3 β₯ -4

as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:

1 β€ 3

1 β₯ -2(3) β 1 β₯ -6

as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.

Part C:

Given that William can only attend a school in her designated zone and that William's zone is defined by y < βx - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 β -3 < -2 - 1 β -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 β -4 < 3 - 1 β -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 β 2 < 4 - 1 β 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 β 4 < -2 - 1 β 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 β 1 < -3 - 1 β 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 β 3 < 2 - 1 β 3 < 1 which is false

Therefore, the schools that WilliamΒ is allowed to attend are the schools at point B and C.

There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is

y β€ x

y β₯ -2x

The system of equation above represent all the points in the first quadrant of the coordinate system.

The area above the line y = -2x and to the right of the line y = x is shaded.

Part B:

It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:

-3 β€ 2

-3 β₯ -2(2) β -3 β₯ -4

as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:

1 β€ 3

1 β₯ -2(3) β 1 β₯ -6

as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.

Part C:

Given that William can only attend a school in her designated zone and that William's zone is defined by y < βx - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 β -3 < -2 - 1 β -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 β -4 < 3 - 1 β -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 β 2 < 4 - 1 β 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 β 4 < -2 - 1 β 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 β 1 < -3 - 1 β 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 β 3 < 2 - 1 β 3 < 1 which is false

Therefore, the schools that WilliamΒ is allowed to attend are the schools at point B and C.