MATH SOLVE

7 months ago

Q:
# Two similar parallelograms have areas 125 m 2 and 80 m 2 . the height of the larger parallelogram is 10 m. what are the lengths of the bases of both parallelograms? solved

Accepted Solution

A:

To solve this problem you must follow the proccedure shown below:

You have that:

- Two similar parallelograms have areas 125 m².

- The height of the larger parallelogram is 10 m. Then, you have:

125=10x

x: the base of the larger parallelogram

x=125/10

x=12.5 m

The ratio is:

b/h=12.5/10

b=1.25h

- The area of the smaller parallelogram is 80 m², then, you have:

80=bh

When you susbstitute b=1.25h into 80=bh, you obtain the value of "h":

80=(1.25h)h

80=1.25h²

h=√(80/1.25)

h=8

Then, the other base is:

b=1.25(8)

b=10 m

The answer is: The base of the smaller parallelogram is 10 m and the base of the larger parallelogram is 8 m.

You have that:

- Two similar parallelograms have areas 125 m².

- The height of the larger parallelogram is 10 m. Then, you have:

125=10x

x: the base of the larger parallelogram

x=125/10

x=12.5 m

The ratio is:

b/h=12.5/10

b=1.25h

- The area of the smaller parallelogram is 80 m², then, you have:

80=bh

When you susbstitute b=1.25h into 80=bh, you obtain the value of "h":

80=(1.25h)h

80=1.25h²

h=√(80/1.25)

h=8

Then, the other base is:

b=1.25(8)

b=10 m

The answer is: The base of the smaller parallelogram is 10 m and the base of the larger parallelogram is 8 m.