What radius of a circle is required to inscribe an equilateral triangle with an area of 15.588 in2 and an altitude of 5.196 in? (round to nearest tenth)
Accepted Solution
A:
Area of triangle = 1/2 base x height15.588 = 1/2 * base x 5.19615.588 = base x 2.598base = 15.588 / 2.598 = 6 equi center of triangle = 1/3*5.196 = 1.732radius of circle = Sqrt(1.732^2 + 3^2) = sqrt (2.999824 +9) = sqrt(11.999824) = 3.464rounded to nearest tenth = 3.5 inches