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Given the quadratic function 3x^(2) =8x-5 what are the values of x?
9 months ago
Q:
Given the quadratic function 3x^(2) =8x-5 what are the values of x?
Accepted Solution
A:
3x^2 = 8x - 5
3x^2 - 8x + 5 = 0 move all terms to one side
3x^2 - 3x - 5x + 5 = 0 split them into two terms
3x(x - 1) - 5(x - 1) = 0 factor out common terms in the first two terms, then the last two terms.
(x - 1)(3x - 5) = 0
x = 1, 5/3
hope this helped, God bless!