MATH SOLVE

9 months ago

Q:
# Given the quadratic function 3x^(2) =8x-5 what are the values of x?

Accepted Solution

A:

3x^2 = 8x - 5

3x^2 - 8x + 5 = 0 move all terms to one side

3x^2 - 3x - 5x + 5 = 0 split them into two terms

3x(x - 1) - 5(x - 1) = 0 factor out common terms in the first two terms, then the last two terms.

(x - 1)(3x - 5) = 0

x = 1, 5/3

hope this helped, God bless!

3x^2 - 8x + 5 = 0 move all terms to one side

3x^2 - 3x - 5x + 5 = 0 split them into two terms

3x(x - 1) - 5(x - 1) = 0 factor out common terms in the first two terms, then the last two terms.

(x - 1)(3x - 5) = 0

x = 1, 5/3

hope this helped, God bless!