MATH SOLVE

8 months ago

Q:
# Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

Accepted Solution

A:

Answer:The dinner costed $48 in total.Step-by-step explanation:The amount of bill paid by Will = 1/4 of billAmount of bill paid by Micah and Sue 1: 3Let us assume the common factor in the ratio = mSo, the amount paid by Micah = 1 x (m) = mThe amount paid by Sue = 3 x (m) = 3 mAlso, amount paid by Sue = $15 + Amount paid by WillSo, the amount paid by Will = amount paid by Sue - $15 = 3 m - $15Total Bill = Bill amount paid by ( Will + Micah + Sue) = m + 3 m + 3 m - 15 = 7 m - 15Now, As will paid 1/4 of total bill.⇒[tex]\frac{1}{4} \times (7 m -15) = 3m -15\\ \implies (7m - 15) = 12 m - 60\\\implies 45 = 5 m \\\implies m = 45/5 = 9[/tex]or, m = 9Now, the total bill = 7 m - 15 = 7(9) - 15 = $48Hence, the dinner costed $48 in total.