MATH SOLVE

10 months ago

Q:
# ONE GEOMETRY QUESTION PLEASE I'M FAILING AND HAVING A MENTAL BREAKDOWN AS WE SPEAK AAAAAAA AAAAAAAAAAhelp me i wanna graduate i got 40 something days please please please please please please please please my mom will disown me if i don't the woman already wants to kick me out i need help just this one please i ha ve a 37 in geometry this is the only class im failing help

Accepted Solution

A:

So this circle has two lines, called tangent lines, coming off of it. How do we know they're tangent lines? They each just touch the circle at a single point (and make a right angle with a radius at that point), R for one, T for the other. And these two lines make an angle. We are asked to find the measure of this angle.

Once you learn this rule, you can apply it easily. The theorem states that if two secant lines, tangent lines, or one of each form an angle outside of the circle, then that angle is half the major arc minus the minor arc [tex] \frac{1}{2}(major \ arc \ - \ minor \ arc)[/tex]. That sounds confusing, I know, but basically we take the major arc TR, which has to be 360° – 134° = 226° (remember, the total has to be 360°, and one piece is 134°), and subtract the minor arc TR, which is 134°, so we get 92°. Remember, we want half of the difference, so half of 92°, which is 46°.

I really hope you are able to pass. Reach out to your teacher, use online resources like Khan Academy, ask classmates, and so on. Best of luck on your gradation!

Once you learn this rule, you can apply it easily. The theorem states that if two secant lines, tangent lines, or one of each form an angle outside of the circle, then that angle is half the major arc minus the minor arc [tex] \frac{1}{2}(major \ arc \ - \ minor \ arc)[/tex]. That sounds confusing, I know, but basically we take the major arc TR, which has to be 360° – 134° = 226° (remember, the total has to be 360°, and one piece is 134°), and subtract the minor arc TR, which is 134°, so we get 92°. Remember, we want half of the difference, so half of 92°, which is 46°.

I really hope you are able to pass. Reach out to your teacher, use online resources like Khan Academy, ask classmates, and so on. Best of luck on your gradation!