Answer:y + 5 = 3(x + 1) → point-slope formy = 3x - 2 → slope-intercept form3x - y = 2 → standard formStep-by-step explanation:The point-slope form of an equation of a line:y - y₁ = m(x - x₁)m - a slope(x₁, y₁) - a point on a lineWe havem = 3, (-1, -5) → x₁ = -1, y₁ = -5Substitute:y - (-5) = 3(x - (-1))y + 5 = 3(x + 1) → point-slope formconvert to the slope-intercept form y = mx + b:y + 5 = 3(x + 1) use the distributive property: a(b + c) = ab + acy + 5 = 3x + 3 subtract 5 from both sidesy = 3x - 2 → slope-intercept formconvert to the standard form Ax + By = C:y = 3x - 2 subtract 3x from both sides-3x + y = -2 change the signs3x - y = 2 → standard form