MATH SOLVE

9 months ago

Q:
# determine a real number so that the polynomial P(x)=2ax³-4x+ax-2a is divisible by x-2 and the remainder is -8

Accepted Solution

A:

Since the given polynomial is divisible by x-2 and the remainder is -8. Using the remainder Theorem, we have:
$$P(2)=-8$$
$$2a(2)^3-4(2)+a(2)-2a=-8$$
$$16a-8=-8$$
$$16a=0$$
$$a=0$$
The required answer is:
$$a=0$$